Electricity Numericals Class 10th

Students find difficulty in solving numerical problems based on electricity and these numericals are always asked in the Class 10^th board exams.

So students must practice electricity class 10 numerical questions.

 

These numericals on electricity mainly consist following topics

    1. Numericals based on electric current

    2. Numericals based on potential and work

    3. Numericals based on Ohm’s law

    4. Numericals based on a combination of resistors

    5. Numericals based on resistivity (specific resistance)

    6. Numericals based on power and energy consumption

    7. Numericals based on the heating effect of electric current

 Numericals Electricity Class 10

1.  An electric motor takes 5 amperes from a 220-volt electric source. Calculate

i.               The power of the motor

ii.           The energy consumed by it in 30 min

Given values 

Electric current (I)= 5 Amp

Potential/voltage (V) = 220 Volt

Time (t) = 30 min = 0.5 Hours

Power (P) =?

Energy consumed =?

Solution 

(i) 

    P=VI

   = 5 ×220 = 1100 Watt

(ii)

Energy consumed = `(Power ×time)/1000`

Energy consumed =` (1100 ×0.5)/1000`

Energy consumed =0.55 kWh or units

2.  Calculate the amount of charge that would flow in 2 hours through the element of an electric bulb drawing a current of 5 Ampere.

Given values 

 Electric current (I)= 5 A

Time(t) =  2 hours = 2× 60×60=7200 s

Solution 

 `I=Q/t`

 Q=I× t

 Q=5× 7200

Q=36000  C

 

3.  In house five bulbs of 60 Watt used for 5 hours, 4 fans of 100 watts are used for 10 hours, and an immersion rod of 1 kW is used for an hour daily. Calculate the energy consumed and total expenditure for April, if one unit cost  Re .2.

Solution 

Energy consumed of 5 bulbs =`(Power × No ×time ×days )/1000`

Energy consumed of 5 bulbs =`(60 ×5×5 ×30 )/1000`

Energy consumed of 5 bulbs =`(45000 )/1000`=45 kWh

Energy consumed of 4 fans  =`(Power × No ×time ×days )/1000`

Energy consumed of 4 fans  =`(100 ×4 ×10 ×30 )/1000`

Energy consumed of 4 fans  =`120000/1000`=120 kWh

Energy consumed of 1 immersion rod  =`(Power × No ×time ×days )/1000`

Energy consumed of 1 immersion rod  =`(1000 ×1 ×1 ×30 )/1000`

Energy consumed of 1 immersion rod  =`30000/1000`=30 kWh

Total energy consumed by all appliances = 45 + 120 +30 = 195 kWh or units

Total expenditure for April 

One unit cost Rs = 2

195  units cost Rs = 2× 195 = 390 Rs.

4.  An electric kettle has rating of 750 W -220 V. calculate

i.              Current passing through it

ii.           Resistance

 Given values 

Power (P) = 750 Watt

Voltage (V) = 220 Volt

Current (I) =?

Resistance (R) =?

Solution 

(i) Calculate current 

      P= VI

     `I=P/V`

      `I=750/220`   =3.40 A

(ii) Calculate Resistance 

     `R=( V)/I`

     `R=( 220)/3.40`   =  64.70 Ohm

5.  Following is the circuit diagram

   Calculate

i.              The current through each resistor

ii.           The total current in the circuit

iii.        The resultant resistance

Given values 

`R_1`= 2 Ohm

`R_2` = 5 Ohm

`R_3` = 30 Ohm

Voltage (V) = 6 Volt

`I_1`= ?

`I_2`= ?

`I_3`=?

Total current (I) =?

Resultant resistance(R)=?

Solution 

(i) Calculate the current through each resistor

 (a) Current through 2 Ohm resistor 

` I_1=V/R_1` 

 `I_1=6/2`=3  A

(b) Current through 5 Ohm resistor 

  `I_2=V/R_2` 

  `I_2=6/5`=1.2 A

(c) Current through 30 Ohm resistor 

  `I_3=V/R_3` 

  `I_3=6/30`=0.2 A

(ii) Total current in the circuit

     `I = I_1 + I_2 + I_3`

     I = 3 + 1.2 + 0.2 = 4.4 A

(iii) The resultant resistance 

       `1/R=  1/R_1 +  1/R_2 +  1/R_3` 

      `1/R=  1/2+1/5+1/30`

     `1/R=  (30+12+2)/60`

     `1/R=  44/60`

    R=  60/44=1.36 Ohm

Numericals on Electricity Video

You can go through other Numerical Problems on Electricity Class 10 

    1. Numerial Based on Electric Current 

   2. Numericals Bases on Heating Effect of Electric Current

    3. Solved Numeicals on Electricity