Explain Activity 1.2 Class 10 NCERT Science

Activity 1.2 Class 10 Science Solution

In this post, you will learn a complete explanation of activity 1.2 class 10 science that belongs to chapter 1 Chemical Reactions and Equations. You can also go through Activity 1.3 of chapter 1 Chemical Reactions and Equations.

Explain Activity 1.2 Class 10 NCERT Science

Caution: This activity needs the teacher’s assistance.

Activity - Take lead nitrate solution in a test tube. Add potassium iodide solution to this. What do you observe?

Observation- On mixing two solutions a yellow colour precipitate of lead iodide is formed.

Pb (NO₃)₂ (aq)    + 2KI (aq) → PbI₂ (s)  + 2KNO₃ (s)

          

Conclusion: On mixing  Pb(NO₃)₂ and KI, the yellow-coloured precipitate of PbI₂ is obtained.

Queries based on activity 1.2 Class 10 Science

1. Give the chemical name of the precipitate formed during this activity.

Ans,-  Lead iodide (PbI₂ )

2. What is a precipitate?

Ans.-  A precipitate is an insoluble substance formed during a chemical reaction.

3. What is a precipitation reaction?

Ans.-  The reaction in which an insoluble substance is formed is called precipitate and the reaction is called a precipitation reaction.

Complete Explanation of activity 1.2 Class 10 Science

 

MCQ Quiz based on Activity 1.2 Class 10 Science

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Related Topics for you

1. Activity 1.3 Class 10 Science

2.  Activity 1.1 Class 10 Science

2. Solution of Chemical Reactions and Equations

3. MCQ Questions of Chapter 1 

4. Extra Questions of Chapter 1

5. How to balance a chemical Reaction

6. What happens during a chemical reaction