Explain Activity 1.2 Class 10 NCERT Science

Activity 1.2 Class 10 Science Solution

In this post, you will learn a complete explanation of activity 1.2 class 10 science that belongs to Chapter 1 Chemical Reactions and Equations. You can also go through Activity 1.3 of Chapter 1 Chemical Reactions and Equations.

Caution: This activity needs the teacher’s assistance.

Material Required

1.  Lead nitrate solution

2.  Potassium iodide solution

3. Test tubes

Activity (Procedure)

First of all, we take a test tube and pour some amount of lead nitrate solution into it.

Now we add some amount of potassium iodide solution into the test tube.

What do you observe?

Observation

After mixing the two solutions, we can see a yellow colour precipitate of lead iodide formed.

Pb (NO₃)₂ (aq)    + 2KI (aq) → PbI₂ (s)  + 2KNO₃ (aq)

Explanation

During the activity, a double displacement reaction takes place between lead nitrate and potassium iodide solution. There is an exchange of ions between both compounds and two new compounds are formed.

During this activity, a yellow-colored precipitate is formed.

 A precipitate is an insoluble solid substance.    

Conclusion: 

This activity shows a double displacement reaction between lead nitrate and potassium iodide solution.

It can also be called a precipitate reaction as an insoluble solid substance[Precipitate]  formed during the activity.

Queries based on activity 1.2 Class 10 Science

1. Give the chemical name of the precipitate formed during this activity.

Ans,-  Lead iodide (PbI₂ )

2. What is a precipitate?

Ans.-  A precipitate is an insoluble substance formed during a chemical reaction.

3. What is a precipitation reaction?

Ans.-  The reaction in which an insoluble substance is formed is called a precipitate and the reaction is called a precipitation reaction.

4. What is the colour of the precipitate formed during the activity?

Ans – A yellow-coloured precipitate is formed.

5. What are the reactants in activity 1.2?

Ans – Lead nitrate and potassium iodide solution.

6. Write the chemical equation for the reaction takes place in the activity?

Ans – Pb(NO₃)₂ + 2KI →PbI_2(s) + 2KNO₃

7. What are the products formed in this activity?

Ans – Lead iodide and potassium nitrate 

8. What is the conclusion of activity 1.2 Class 10 Science?

Ans – In this activity, a double displacement reaction takes place

9. What is the chemical formula of lead nitrate?

Ans – Pb(NO3)2

10. What are the characteristic features of the activity?

Ans – Formation of insoluble solid substance (precipitate)

Complete Explanation of Activity 1.2 Class 10 Science

 

MCQ Quiz based on Activity 1.2 Class 10 Science

Related Topics for you

1. Activity 1.3 Class 10 Science

2.  Activity 1.1 Class 10 Science

2. Solution of Chemical Reactions and Equations

3. MCQ Questions of Chapter 1 

4. Extra Questions of Chapter 1

5. How to balance a chemical Reaction

6. What happens during a chemical reaction